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Big Ideas Math Integrated I, 2016

BI

Big Ideas Math Integrated I, 2016 View details

Chapter Review

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Exercise 18 Page 95

Isolate s on the right-hand side. Start with distributing 2.

Inequality: s≤ 143
Graph:

Practice makes perfect

To solve the inequality, we should use inverse operations to isolate s. We start with distributing 2 to each term inside the parentheses.

2(-4s+2)≥-5s-10

Distribute 2

(2)(-4s)+(2)2≥-5s-10

Multiply

-8s+4≥-5s-10

LHS+8s≥RHS+8s

4≥3s-10

LHS+10≥RHS+10

14≥3s

.LHS /3.≥.RHS /3.

14/3≥ s

Rearrange inequality

s≤14/3

This inequality tells us that all values less than or equal to 143 will satisfy the inequality. Below we demonstrate the inequality by graphing the solution set on a number line. Notice that s can equal 143, which we will show with a closed circle on the number line.

Subchapter links

1 Writing and Graphing Inequalities p.94

2 Solving Inequalities Using Addition or Subtraction p.94

3 Solving Inequalities Using Multiplication or Division p.95

4 Solving Multi-Step Inequalities p.95

5 Solving Compound Inequalities p.96

6 Solving Absolute Value Inequalities p.96