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Big Ideas Math Integrated I, 2016

BI

Big Ideas Math Integrated I, 2016 View details

4. Solving Absolute Value Equations

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Exercise 67 Page 34

The perimeter of a rectangle can be found by adding twice its length l and twice its width w.

9 cm

Practice makes perfect

We are given a rectangle which has a width of 4 centimeters and a perimeter of 26 centimeters. We are asked to find its length.

Because opposite sides in a rectangle are the same length, the perimeter of a rectangle can be found by multiplying its length l and width w by 2, then adding those two values. P=2l+2w To find l, we can substitute P= 26 and w= 4 into the formula, then solve.

P=2l+2w

P= 26, w= 4

26=2l+2( 4)

Multiply

26=2l+8

LHS-8=RHS-8

18=2l

.LHS /2.=.RHS /2.

9=l

Rearrange equation

l=9

The length of the rectangle is 9 centimeters.

Subchapter links

Communicate Your Answer p.27

Monitoring Progress p.28-31

Exercises p.32-34