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Big Ideas Math Integrated I, 2016

BI

Big Ideas Math Integrated I, 2016 View details

4. Solving Absolute Value Equations

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Exercise 23 Page 32

How many cases do you have after you remove the absolute value?

Solutions: s=20
Number Line:

Practice makes perfect

Before we can solve this equation, we need to isolate the absolute value expression using the Properties of Equality.

3=- 2|1/4s-5|+3

LHS-3=RHS-3

0=- 2|1/4s-5|

.LHS /(- 2).=.RHS /(- 2).

0=|1/4s-5|

Rearrange equation

|1/4s-5|=0

An absolute value measures an expression's distance from a midpoint on a number line. |1/4s-5|= 0 This equation means that the distance between 14s and 5 is 0. Therefore the expression inside the absolute value needs to equal 0. |1/4s-5|= 0 ⇕ 1/4s-5=0 Let's solve this equation for s.

1/4s-5=0

LHS+5=RHS+5

1/4s=5

LHS * 4=RHS* 4

s=20

The solution to absolute value equation is 20. Let's graph this solution on a number line.

Subchapter links

Communicate Your Answer p.27

Monitoring Progress p.28-31

Exercises p.32-34