body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Big Ideas Math Integrated I, 2016

BI

Big Ideas Math Integrated I, 2016 View details

4. Solving Absolute Value Equations

Continue to next subchapter

Exercise 63 Page 34

What do you need to do to get from Equation 1 to Equation 2?

Division Property of Equality

Practice makes perfect

Let's take a look at the two equations. We are asked to find the Property of Equality that makes them equivalent.

When comparing Equation 1 and Equation 2, we see that each of the sides became 4 times smaller. For that to happen, both sides of Equation 1 must have been divided by 4. 4y=28 ⇔ 4y ÷ 4=28 ÷ 4 Let's simplify the resulting equation by calculating the quotients on both sides.

4y ÷ 4 = 28÷ 4

a÷ b=a/b

4y/4=28/4

Calculate quotient

y=7

We got the second equation. Since we were dividing both sides of an inequality, this property is called the Division Property of Equality.

Subchapter links

Communicate Your Answer p.27

Monitoring Progress p.28-31

Exercises p.32-34