Exercise 5 Page 26

To solve an equation, we should first gather all of the variable terms on one side and all of the constant terms on the other, using the Properties of Equality. In this case, we start by adding 3 to both sides of the equation. The next step is to isolate m on the left-hand side. We can do that by using the Division Property of Equality to divide both sides of the equation by 2.

2m=16

DivEqn

.LHS /2.=.RHS /2.

2m/2=16/2

CalcQuot

Calculate quotient

m=8

We can check our solution by substituting it into the original equation and simplifying. If doing so results in an identity, our solution is correct. An identity is when both sides of the equation are exactly the same.

2m-3=13

Substitute

m= 8

2( 8)-3? = 13

Multiply

Multiply

16-3? =13

SubTerm

Subtract term

13=13

Because the left and right-hand sides of the equation are the same, we know that m=8 is the correct solution.