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Big Ideas Math Integrated I, 2016

BI

Big Ideas Math Integrated I, 2016 View details

1-3. Quiz

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Exercise 7 Page 26

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

w=1/5

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side and all of the constant terms on the other, using the Properties of Equality. In this case, we start by combining like terms.

5=7w+8w+2

Add terms

5=15w+2

LHS-2=RHS-2

5-2=15w+2-2

Subtract terms

3=15w

.LHS /15.=.RHS /15.

3/15=w

a/b=.a /3./.b /3.

1/5=w

Rearrange equation

w=1/5

Let's check our solution by substituting w= 15 into the original equation. If doing so results in an identity, our solution is correct. An identity is when both sides of the equation are exactly the same.

5=7w+8w+2

w= 1/5

5? =7( 1/5)+8( 1/5)+2

MoveLeftFacToNumOne

a* 1/b= a/b

5? =7/5+8/5+2

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Simplify RHS

Add fractions

5? =15/5+2

Calculate quotient

5? =3+2

Add terms

5=5

Because both sides are equal, we know that our answer is correct.