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Big Ideas Math Integrated I, 2016

BI

Big Ideas Math Integrated I, 2016 View details

1-3. Quiz

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Exercise 12 Page 26

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

n=- 9

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side and all of the constant terms on the other, using the Properties of Equality.

- 8-5n=64+3n

LHS-3n=RHS-3n

- 8-5n-3n=64+3n-3n

Subtract terms

- 8-8n=64

LHS+8=RHS+8

- 8-8n+8=64+8

Add terms

- 8n=72

Finally, we need to divide both sides by - 8 to fully isolate n.

- 8n=72

.LHS /(- 8).=.RHS /(- 8).

- 8n/- 8=72/- 8

Calculate quotient

n=- 9

Therefore, n=- 9 is the solution to the equation.