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Big Ideas Math Integrated I, 2016

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Big Ideas Math Integrated I, 2016 View details

1-3. Quiz

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Exercise 3 Page 26

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

r=- 5

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side and all of the constant terms on the other, using the Properties of Equality.

60=- 12r

.LHS /(- 12).=.RHS /(- 12).

60/- 12=- 12r/- 12

Calculate quotient

- 5=r

Rearrange equation

r=- 5

We will check our solution by substituting this result back into the original equation and simplifying. If doing so results in an identity, our solution is correct. An identity is when both sides of the equation are exactly the same.

60=- 12r

r= - 5

60? =- 12 ( - 5)

Multiply

60=60

Since substituting r=- 5 resulted in an identity, our solution is correct.