Big Ideas Math Integrated I, 2016
BI
Big Ideas Math Integrated I, 2016 View details
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Exercise 7 Page 47

Start by distributing 3 to each term inside the parentheses.

x=-6

Practice makes perfect
On the left-hand side, we have a product of 3 and an expression in parentheses. To evaluate this product, we distribute 3 to each term inside the parentheses.
3(x+4)-1=-7
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Distribute 3
3(x)+3(4)-1=-7
3x+12-1=- 7
3x+11=-7
Now we can continue solving for x using inverse operations.
3x+11=-7
â–Ľ
LHS-11=RHS-11
3x+11-11=-7-11
3x=-18
â–Ľ
3x/3=-18/3
3x/3=-18/3
x=-6