Next we are asked to find the value of w and determine the width of the field. In the figure, we are given that the perimeter is 330 yards and the length is 100 yards. Let's insert these values into the rewritten equation.
Lastly, we are asked to determine what percent of the field is inside the indicated circle. We can use the percent proportion to solve this problem.
Part/Whole=Percent/100
In the equation, part is the circle's area. We can calculate this since we know its radius, r= 10 yards.
A_C=Ï€ * r^2
⇕
A_C=Ï€ * 10^2=100Ï€ yd^2
In the denominator, whole represents the entire area of the rectangular field, which is simply its width w times its length l.
A_R= w * l
⇕
A_R= 65* 100=6500
Now let's plug these values into our formula.
