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Isolate x on one side of the equation.
x=-1/5
We need to isolate x on one side to solve the equation. By using the Subtraction Property of Equality twice, we can collect all the x-values on the left-hand side and all of the constant terms on the other side of the equation.
LHS-x=RHS-x
Subtract terms
LHS-1=RHS-1
.LHS /10.=.RHS /10.
Calculate quotient
The solution is x=- 15. We can check our solution by substituting it into the original equation.
x= -1/5
Put minus sign in numerator
a*b/c= a* b/c
Rewrite 1 as 5/5
Remove parentheses
Add fractions
Since the left-hand side is equal to the right-hand side, our solution is correct.
