Big Ideas Math Algebra 2, 2014
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Big Ideas Math Algebra 2, 2014 View details
5. Solving Polynomial Equations
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Exercise 63 Page 196

Express the length of the ramps in terms of x.

Description Dimension
Height of each ramp 5/3 feet
Width of each ramp 5 feet
Length of the left ramp 24 feet
Length of the right ramp 12 feet
Practice makes perfect

We can find the dimensions of the ramps in three steps.

  1. First, we will express the length of each ramp in terms of x.
  2. Next, we will express the total volume of the ramps in terms of x.
  3. We will find x and the dimensions of the ramps.

Length of the Ramps

Let's introduce the variables y and z for the length of the ramps. We are given that the left ramp is twice as long as the right ramp, so y=2z. The diagram gives the total length of the two ramps and the opening. This allows us to set up and solve an equation for z.
y+3x+z=21x+6
2z+3x+z=21x+6
â–Ľ
Solve for z
3x+3z=21x+6
3z=18x+6
z=6x+2
Since y=2z, this also gives the length of the left ramp. 2 &Length of right ramp:&& z=6x+2 &Length of left ramp:&& y=2z=12x+4

Volume of the Ramps

Let's summarize the dimensions of the ramps in terms of x.
Left Ramp Right Ramp
Length 12x+4 6x+2
Width 3x 3x
Height x x
The volume of each ramp is half the product of its length, width, and height. Let's write and expand the expression of the volume of the left ramp first.
V_L=1/2(x)(3x)(12x+4)
â–Ľ
Simplify right-hand side
V_L=3/2x^2(12x+4)
V_L=18x^3+6x^2
Similarly, we can get an expression of the volume for the right ramp.
V_R=1/2(x)(3x)(6x+2)
â–Ľ
Simplify right-hand side
V_R=3/2x^2(6x+2)
V_R=9x^3+3x^2
The total volume of the two ramps is the sum of these two expressions.
V=V_L+V_R
V=18x^3+6x^2+9x^3+3x^2
V=27x^3+9x^2

Finding x

We are given that the total volume of the ramps is 150 cubic feet. Let's use this information to set up an equation for x.
27x^3+9x^2=150
27x^3+9x^2-150=0
According to the Rational Root Theorem, all rational solutions of this equation are quotients of a factor of the constant term, 150, and a factor of the leading coefficient, 27. Let's list these factors.
Coefficient Factors
150 ± 1, ± 2, ± 3, ± 5, ± 6, ± 10, ± 15, ± 25, ± 30, ± 50, ± 75, ± 150
27 ± 1, ± 3, ± 9, ± 27

Even if we only consider the positive values since x represents a length, these are a lot of possibilities to try. Let's use instead a calculator to draw the graph and find the x-intercept. We begin by pushing the Y= button and typing the equation in the first row.

To see the graph, you will need to adjust the window. Push WINDOW, change the settings, and push GRAPH.

To find the x-intercept of the graph, push 2nd and TRACE and choose zero from the menu. The calculator will prompt you to choose a left and right bound and to provide the calculator with a best guess of where the zero might be.

The calculator gives that the approximate value of the solution is 1.6666667. Let's compare this to the list of factors of the constant term and the leading coefficient. We can see that it is close to 53, which is a possible solution according to the Rational Root Theorem. Let's check this value.
27x^3+9x^2-150=0
27( 5/3)^3+9( 5/3)^2-150? =0
â–Ľ
Evaluate left-hand side
27*125/27+9*25/9-150? =0
125+25-150? =0
0=0
Combining the graphing and algebraic approach, we found the exact solution of the equation. x=5/3

Dimensions of the Ramps

Using x= 53, we can find the dimensions of the ramps.

Description Expression Dimension
Height of each ramp (x) 5/3 5/3 feet
Width of each ramp (3x) 3(5/3) 5 feet
Length of the left ramp (12x+4) 12(5/3)+4 24 feet
Length of the right ramp (6x+2) 6(5/3)+2 12 feet