Big Ideas Math Algebra 2, 2014
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Big Ideas Math Algebra 2, 2014 View details
5. Solving Polynomial Equations
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Exercise 40 Page 195

Use the Rational Root Theorem.

4, -3/2, and -5/2

Practice makes perfect

The Rational Root Theorem tells us the possible fully simplified rational zeros of a polynomial function with integer coefficients.

  • If pq is a solution of a_nx^n+... a_1+ a_0=0, then p is a factor of the constant term a_0.
  • If pq is a solution of a_nx^n+... a_1+a_0=0, then q is a factor of the leading coefficient a_n.
We first must identify the leading coefficient and the constant term in our polynomial. 4x^3-49x+( -60) Let's list all possible values of the numerator and denominator of a rational zero.
Description Values
The possible values of the numerator are the factors of the constant term -60. ± 1, ± 2, ± 3, ± 4, ± 5, ± 6, ± 10, ± 12, ± 15, ± 20, ± 30, ± 60
The possible values of the denominator are the factors of the leading coefficient 4. ± 1, ± 2, ± 4

Now we can list all possible rational zeros.

Denominator
±1 ±2 ±4
Numerator ± 1 ±1 ±1/2 ±1/4
± 2 ±2 ±1 ±1/2
± 3 ±3 ±3/2 ±3/4
± 4 ±4 ±2 ±1
± 5 ±5 ±5/2 ±5/4
± 6 ±6 ±3 ±3/2
± 10 ±10 ±5 ±5/2
± 12 ±12 ±6 ±3
± 15 ±15 ±15/2 ±15/4
± 20 ±20 ±10 ±5
± 30 ±30 ±15 ±15/2
± 60 ±60 ±30 ±15

Let's compare these values to the x-intercepts of the graph.

We can see that there are three reasonable possibilities. x=- 5/2, x=- 3/2, x=4 Let's use synthetic division to check x=4 first. rl IR-0.15cm r 4 & |rr 4& 0& -49& -60 & 16& 64& 60 & c 4& 16 & 15 & 0 We can see that x=4 is indeed a zero, and we also get the factor form of the polynomial. 4x^3-49x-60=(x-4)(4x^2+16x+15) To find the other zeros, we set the quadratic factor equal to 0 and use the Quadratic Formula to solve the equation. For this, we need the coefficients of the quadratic. ax^2+bx+c=4x^2+16x+15 ⇓ a=4, b=16, c=15
4x^2+16x+15=0
x=- 16±sqrt(16^2-4( 4)( 15))/2( 4)
â–Ľ
Evaluate right-hand side
x=- 16±sqrt(256-240)/8
x=- 16±sqrt(16)/8
x=-16± 4/8
We now have all three zeros of the function. 4, -16+4/8=-3/2, -16-4/8=-5/2