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| | 12 Theory slides |
| | 13 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Here are a few recommended readings before getting started with this lesson.
What would the product be if the side length of each square was 0.1 unit long?In that case, could the rectangle be used to represent 0.2* 0.3? Help Zosia answer the following questions.
Zosia likes singing. She decides to record a video of herself singing.
She records two video clips. The first video clip is 4.56 minutes long and the second is 5.54 minutes long.
Recall the steps to follow to add and subtract decimals. First, align the decimal numbers by their place values, one below the other. Then, perform the operation just like as if the numbers were integers. Finally, place the decimal point to the answer. Follow these steps to find the sum or difference shown in the applet.
The factors in the product will be rounded to the greatest place value to make it easier to compute mentally. In the first factor 35.92, the digit with the greatest place value is 3. In the other factor 0.014, the digit with the greatest place value is 1. 35.92 * 0.014 Next, look at the digit to the right of the greatest place.
Next, make all digits to the right of the greatest place value zero. For 35.92, the digit to the right of the greatest place value is 5. For 0.014, the digit to the right of the greatest place value is 4.
| Estimate 35. 92 * 0.014 | ||
|---|---|---|
| Factor | Greatest Place Value | Digit to the Right |
| 3 5.92 | Tens | 5 |
| 0.01 4 | Hundredths | 4 |
Now multiply the rounded numbers. Since 0.01 is 10^(- 2), it will move the decimal point in the other factor two places to the left. cr & 40 * & 0.01 & 0.40 The given product is about 0.4. 35.92 * 0.014 ≈ 0.4
Zosia shares her video on a video sharing platform.
Mark, Zosia's brother, promises to pay Zosia $1.75 for each view of her video. So far, 59 people have watched the video.
59 * 1.75 Each factor will be rounded to the greatest place value to estimate this product. In the number 59, the digit with the greatest place value is 5. In the other factor, the digit with the greatest place value is 1. 59 * 1.75 Now, take a look at the digit to the right of the greatest place value.
After that, make all digits to the right of the greatest place value zero. Starting with the first factor, the digit to the right of the underlined number is 9. This is greater than 5, so the digit in the rounded place is increased by 1 and the other digit is changed to a 0. ccc 5 9 & * &1.75 ↓ & & 60 && For 1.75, the number in the tenths place is 7. Since 7 is greater than 5, the number in the rounded place 1 is increased by 1 and the other digits are converted to 0. In this case, the zeros can be ignored because they will not change the value of the product. ccc 59 & * &1. 75 ↓ & & ↓ 60 & * &2 The product of 60 and 2 is 120. Mark will pay about 120 dollars.
59 * 1.75 The steps for multiplying these numbers is the same as multiplying two decimal numbers.
In addition to the amount that Mark gives her, Zosia also earns money per view from the video sharing platform.
The platform pays 0.113 times what Mark paid for 59 views.
103.25 * 0.113 The digit to the right of the greatest place value determines how the number is rounded.
Multiply the decimal numbers. Make sure that the decimal point is placed correctly!
Since the area of a square is the product of its two sides, this square has an area of 0.1* 0.1 square units. 0.1 * 0.1 Now multiply the decimals as if they were whole numbers. 1 * 1 =1 Then, count the number of decimal places in each factor and add them. rr 0. 1 * 0. 1 & l→ → & r 1 decimal place + 1 decimal place 2 decimal places The number of decimal places in the product must be 2. Insert zeros to the left of 1 and move the decimal point two places to the left. rr 0. 1 * 0. 1 0. 01 & l→ → ← & r 1 decimal place + 1 decimal place 2 decimal places The area of a single square is 0.01 square unit.
In the previous part, it is found that the area of a each square is 0.01.
Rewrite 0.2 as 2 * 0.1
Rewrite 0.3 as 3 * 0.1
Associative Property of Multiplication
Commutative Property of Multiplication
Associative Property of Multiplication
Multiply
Multiply
Paulina finds the difference of 8.7 and 6.27 as shown in the diagram.
We are given a diagram that shows how Paulina subtracts two decimal numbers.
We want to determine whether she correct. We can see that Paulina correctly lined up the decimal points. However, she did not add a zero to the first number. Additionally, she brought down 7 in the hundredths place of the second decimal number like it was an addition. Let's now complete the steps that Paulina skipped and find the difference.
We got a different result. This means that Paulina is not correct and the correct answer is 2.43, which corresponds to option B.
Tiffaniqua's family has a triangular garden. The dimensions of the graden are shown in the diagram.
We need to add up the lengths of each side of the garden to find the length of the fence that they need to enclose it. 19.4 + 25.63 + 26.75 Let's first add the first two terms. We line up the digits according to their place values. Note that we need to add a zero to the first number so that each place has a digit. & 1 9 . 4 0 + & 2 5 . 6 3 We will add the decimals just like we do with whole numbers and place the decimal point in the answer.
Next, we will add the third side to the sum of the first two terms. 45.03+ 26.75 Again we will line up the decimal points so that place-value positions line up with each other. In this case, both numbers have the same number of decimal places, so we do not need add any zeros. & 4 5 . 0 3 + & 2 6 . 7 5 We will now add the decimals just like we do with whole numbers and place the decimal point in the answer.
This means that the family needs 71.78 meters of fencing to enclose the garden.
Jordan finds the result of an addition expression.
Jordan found the result of the given addition expression. 3.14 + 3.14 + 3.14 + 3.14 = 12.56 We want to find the missing factor of the product equal to the sum. 3.14 * = 12.56 We can see that the sum of the same four addends is equal to 12.56. Since the addends are the same and equal to each other, we can write the addition as a multiplication of four times 3.14. 3.14* 4 = 12.56 This means that the number we are looking for is 4.
Let's estimate the product of the numbers in the first group. We can see that for all factors, the greatest place value is the ones place. 5. 9 & * & 4. 9 & * & 6. 9 For each of the factors, the digit to the right of the greatest place is 9, which is greater than 5. This means that we increase the digit in the ones place of each number by 1 and ignore the decimal parts. 5.9 & * & 4.9 & * & 6.9 ↓ & & ↓ & & ↓ 6 & * & 5 &* & 7 The product of these rounded numbers is 210, so the product of the original numbers is about 210. We can eliminate option I since it does not equal approximately 60. Let's round the numbers in the other groups and estimate their products.
| Group | Round Numbers | Multiply |
|---|---|---|
| I | ccc 5.9 & → & 6 4.9 & → & 5 6.9 & → & 7 | 6 * 5 * 7 = 210 |
| II | ccc 2.9 & → & 3 4.1 & → & 4 5.1 & → & 5 | 3 * 4 * 5 = 60 |
| III | ccc 2.1 & → & 2 4.9 & → & 5 5.9 & → & 6 | 2 * 5 * 6 = 60 |
| IV | ccc 1.9 & → & 2 5.9 & → & 6 9.4 & → & 9 | 2 * 6 * 9 = 108 |
| V | ccc 1.15 & → & 1 12.3 & → & 10 5.95 & → & 6 | 1 * 10 * 6 = 60 |
The numbers in the groups II, III, and V have a product of about 60.
We want to find the weight of the Perseverance rover on Mars. We can do this by multiplying 1.025 by 0.38. 1.025* 0.38 We will multiply these numbers just as we do with two whole numbers to find the product. Let's ignore the decimal points for the moment. lr & 1 0 2 5 * & 3 8 & 8 2 0 0 + &3 0 7 5 0 & 3 8 9 5 0 Now we can place the decimal point in the product by counting the number of decimal places in each factor. The number of decimal places in the product is the sum of the decimal places in the factors. cr & 1. 025 * & 0. 38 & 8200 + & 30750 & 0. 38950 l ⟶ ⟶ ⟵ cl & 3 decimal places + & 2 decimal places & 5 decimal places This means that a 1.025-ton vehicle weighs about 0.3895 tons on Mars.