Let A(n) be the representing the amount of money left on Elishia's card. At the beginning the cafeteria card's value is $50. This means that our first term, A(1), is 50. After the first purchase on Monday its value is $46.75, and after the next day its value is $43.50. 50→−3.2546.75→−3.2543.5→−3.25…
As we can see the common difference d is equal to -3.25.
Finding our formula
We will use the generic form of an of an arithmetic sequence.
A(n)=A(1)+(n−1)d
In the above formula,
A(1) is the initial value and
d is the common difference. We will get our equation by substituting
A(1)=50 and
d=-3.25.
A(n)=A(1)+(n−1)d
A(n)=50+(n−1)(-3.25)
A(n)=50+(-3.25)(n−1)
A(n)=50−3.25(n−1)
Finding the value of the card
Each lunch decreases the value of the card by
$3.25. Therefore, to find the amount of money left on the card after buying
12 lunches, we should subtract
12⋅3.25 from the initial value
50.
After buying
12 lunches, the card's value will be
$11.