follow a specific format.
an=a1+(n−1)d
In this form,
a1 is the first term in a given sequence,
d is the from one term to the next, and
an is the
nth term in the sequence. For this exercise, the first term is
a1=100. Let's observe the other terms to determine the common difference
d.
100→+10110→+10120→+10130…
As we can see
d=10. By substituting these two values we found into the explicit equation and simplifying, we can find the formula for this sequence.
an=a1+(n−1)d
an=100+(n−1)(10)
an=100+10n−10
an=10n+90
This equation can be used to find
any term in the given sequence. To find
a10, the
10th term in the sequence, we substitute
10 for
n.
an=10n+90
a10=10(10)+90
a10=100+90
a10=190
The
10th term in the sequence is
190.