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$m=x_{2}−x_{1}y_{2}−y_{1} $

$m=2−1270000−281000 $

$m=-11000$

$y=mx+b$

Substitute$m=-11000$

$y=(-11000)x+b$

$270=-11(2)+b$

Simplify

MultiplyMultiply

$270000=-22000+b$

AddEqn$LHS+22000=RHS+22000$

$292000=b$

RearrangeEqnRearrange equation

$b=292000$

b

We know the weights of the box after taking out each item. Hence, if we calculate the differences between consecutive weights, we will know the weight of each item. $281000−270000270000−259000259000−248000 =11000=11000=11000 $ The weight of each yearbook is $11000$ ounces.

c

It is given that the weight of the box when full is $292000$ ounces, and when it's empty is $17000$ ounces. Therefore, by subtracting $17000$ from $292000$ we can calculate the weight of all of the items, not including the weight of the box. $292000−17000=275000ounces $ Now if we divide this weight by the weight of $1$ book, we will know how many items were in the box. $11000272000 =25items $ There were $25$ items in the box.