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| | 19 Theory slides |
| | 13 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Mark is building a model of the house of his dreams. He enjoys constructing different rooms and furniture from various materials. He also wants to build a dog house for his toy dog Bubbles.
Prisms can be categorized by the shape of their bases. For example, a prism with a triangular base is called a triangular prism. A rectangular prism, on the other hand, has a rectangular base.
A cube is a three-dimensional solid object bounded by six square faces with three meeting at each vertex. All square faces have the same side length. A cube is a specific type of rectangular prism.
Determine whether the given solid is a triangular prism, a rectangular prism, or neither.
There are two important characteristics that give information about 3D objects.
The volume of a solid is the measure of the amount of space inside the solid. It is the three-dimensional equivalent of the area of the figure. Volume is measured using cubic units, such as cubic meters, or m^3. The applet below illustrates the volume of some solids. Move the slider to fill the solids.
The surface area SA of a three-dimensional shape is the total area of all the surfaces of the shape. The lateral area LA is the total area of all lateral surfaces, the surfaces of the shape that are not bases. Lateral area can be defined for polyhedrons, cones, and cylinders. In these instances, the surface area of the shape can be calculated by the formula below.
SA=LA+Area of the Bases
The net of a solid can be helpful to visualize the surfaces of a three-dimensional figure.
Consider a prism with a base area B and height h.
The volume of the prism is calculated by multiplying the base's area by its height.
V = Bh
By Cavalieri's principle, this formula holds true for all types of prisms, including skewed ones.
Additionally, the prism is, so to speak, filled
with identical base areas that are stacked on top of each other to the height of the prism.
This means that the volume of the prism can be calculated as the sum of all these base areas. The number of bases is equal to the height of the prism. Therefore, the volume of a prism equals the product of its base area and height. V=B+B+B+...+B+B_h ⇓ V=B* h
Consider a prism with a height h, base area B, and base perimeter P.
The surface area of the prism is the sum of the two base areas and the lateral area, which can be calculated as the product of the base perimeter and the height of the prism.
SA=2B+Ph
Notice that the lateral surface consists of rectangles equal to the number of sides in the base. The pentagonal prism shown here has five lateral faces because a pentagon has five sides. The area of each rectangular lateral face is the product of its sides a and h. One Lateral Face A=ah If there are n rectangular lateral faces in a prism, then the total lateral area is the product of n and the area of one lateral face. Lateral Area nah Notice that na is the perimeter of the base, which is often denoted by P. Then, the lateral area can be expressed as follows. Lateral Area= Ph Therefore, the formula for the surface area is obtained.
ccccc Surface Area & = & Lateral Area & + & 2* Base [0.8em] SA & =& Ph & + & 2B
Note that although this proof is written for a regular prism, it is also true for a non-regular prism.
It is possible to derive two specific formulas for the volume and surface area of a rectangular prism.
Consider a rectangular prism with a width w, length l, and height h.
The volume of the prism is calculated by multiplying the area of the base by the height of the prism.
V = wl h
Consider a rectangular prism with a height h, base area B, and base perimeter P.
The surface area of the rectangular prism can be found using the following formula.
SA=2(wl+hl+hw)
P= 2(w+l), B= wl
Distribute h
Factor out 2
This process results in the formula for the surface area of a rectangular prism.
Consider a cube with a side length s.
The volume V of the cube can be calculated by raising the side length s to the power of 3, or cubing
it.
V=s^3
The formula for the volume of a cube can therefore be derived by substituting s into the standard equation for the volume of a rectangular prism.
Consider a cube with a side length s.
The surface area of the cube is given by the following formula.
SA=6s^2
Substitute values
a* a=a^2
Add terms
Mark wants to start painting the walls in the model bedroom and fill it with furniture. To understand how much paint he needs and how much space is available, Mark has to determine the surface area and the volume of the room. He starts by measuring the dimensions of the room.
V=wl h Here, w is the width, l is the length, and h is the height of the prism. The diagram shows that the width of the room is 3.5 inches, the length is 4 inches, and the height is 2.7 inches. Substitute these values into the formula and evaluate.
The volume of the room is 37.8 cubic inches.
SA=2(wl+hl+hw) Substitute w with 3.5, l with 4, and h with 2.7 into the formula and simplify.
Substitute values
Multiply
Add terms
Multiply
The surface area of the bedroom is 68.5 square inches.
Later in the day, Mark decides to work on the bedroom closet, which also has a rectangular prism shape. His measurements show that the length of the closet is 1.4 inches and its height is 2 inches, but he is not able to measure the width since the closet was already installed in the wall.
Substitute values
Multiply
Commutative Property of Multiplication
Rearrange equation
.LHS /2.8.=.RHS /2.8.
Use a calculator
The width w of the closet is 1.25 inches. Now there is enough information to calculate the surface area of the closet. Substitute the values into the formula for the surface area of a rectangular prism and evaluate SA.
Substitute values
Multiply
Add terms
Multiply
The surface area of the closet is 14.1 square inches.
After mostly finishing with the first floor, Mark begins brainstorming ideas for the design of the attic. He needs to determine how much space there is in the attic and the areas of the walls, floor, and ceiling.
V=Bh Here, B is the area of one base and h is the height of the prism. The base of a triangular prism is a triangle, so recall the formula for the area of a triangle. A=1/2bh The diagram shows that the base of the triangle is 7 inches and its height is 2.3 inches. Substitute 7 for b and 2.3 for h in the formula and solve for A.
b= 7, h= 2.3
Multiply
1/b* a = a/b
Calculate quotient
The area of the triangle, and therefore the base area of the prism, is 8.05 square inches. Now that this value is known, substitute B= 8.05 and h= 9 in the formula for the volume of a prism.
The volume of the attic is 72.45 cubic inches.
SA=2B+Ph In this formula, B is the area of one base, P is the perimeter of the base, and h is the height of the prism. The lengths of all the sides of the triangular base are given on the diagram. Find the perimeter of the triangle by adding all the side lengths together. P=7+4.2+4.2= 15.4 in. In Part B it was found that the base area is 8.05 square inches. Substitute B= 8.05, P= 15.4, and h= 9 into the formula for the surface area of a prism and evaluate SA.
Substitute values
Multiply
Add terms
The surface area of the attic is 154.7 square inches.
Finally, Mark noticed that there is some empty space above the living room next to the upstairs bathroom. He wants to potentially turn in into another room. Mark knows that the surface area of that room would be 79.8 square inches.
b= 4, h= 2.7
Multiply
1/b* a = a/b
Calculate quotient
The area of the triangular base of the prism is 5.4 square inches. Next, add the side lengths of the triangle to calculate the perimeter of the base of the prism. P=4+2.7+4.8= 11.5in. Now every value in the formula for the surface area of a triangular prism is known except for its height h. Mark knows that the surface area of the potential room is 79.8 square inches. Substitute 79.8 for SA, 5.4 for B, and 11.5 for P into the formula and solve for h.
Substitute values
Multiply
LHS-10.8=RHS-10.8
Rearrange equation
.LHS /11.5.=.RHS /11.5.
The height of the prism is 6 inches. Finally, find the volume of the prism by using the following formula. V=Bh Substitute 5.4 for B and 6 for h, then evaluate for V.
The volume of the potential room is 32.4 cubic inches.
Calculate the volume or surface area of the triangular or rectangular prism given the base area B, the height, and the side length of the base. The base is always a regular polygon. Round the answer to one decimal place if necessary.
As mentioned before, Mark is building a model of the house of his dreams. He also wants to build a dog house for his toy dog Bubbles.
The volume of a triangular prism can be found by using the general formula for the volume of a prism. V=Bh Here, B is the area of one base and h is the height of the prism. This means that the area of the base must be found first to apply this formula. The base of this prism is a triangle, which means that its area is half the product of its base b and height h. A=1/2bh The diagram shows that the triangle has a height of 1 inch and a base length of 1.2 inches. This information can be used in the formula to calculate the area.
h= 1, b= 1.2
1* a=a
1/b* a = a/b
Calculate quotient
The area of the base is 0.6 square inches. Now multiply this area by the height of the prism, 2 inches, to find the volume of the prism.
B= 0.6, h= 2
Multiply
The volume of the triangular prism is 1.2 cubic inches.
The volume of a rectangular prism can be calculated using the following formula. V=wl h Here, w is the width, l is the length, and h is the height of the prism. The diagram shows that the width of the prism is 0.8 inches, the length is 1 inch, and the height is 2 inches. Substitute these values into the formula.
Substitute values
Multiply
The volume of the rectangular prism is 1.6 cubic inches.
Finally, the volumes of the prisms can be compared.
| Volume of the Triangular Prism | Volume of the Rectangular Prism |
|---|---|
| 1.2in.^3 | 1.6in.^3 |
The volume of the rectangular prism is greater than the volume of the triangular prism. This means that the dog house in the shape of the rectangular prism is more spacious, so Mark should choose that one.
Izabella made a figure by placing a cube with 11-centimeter sides on top of another cube with 13-centimeter sides.
She wants to paint the entire figure green. To determine how much paint she needs, find the surface area of the figure.
We are given the following figure and are asked to find the surface area. Let's start by analyzing the diagram.
The figure consists of two cubes. We can find their surface areas to get the desired area to be painted. However, notice that the smaller cube's lower base is adjacent to part of the larger cube's upper base. This means that the figure's surface area does not include the area of the smaller cube's lower base and an equally large part of the larger cube's upper base.
The surface area of the figure is the surface area of the smaller cube plus the surface area of the larger cube minus twice the area of the smaller cube's base. Let's find these areas one at a time, starting with the smaller cube. Recall that the surface area of a cube with a side length s can be calculated by using the following formula. S = 6s^2 Let's substitute 11 for s into the formula and find the surface area of the smaller cube.
The surface area of the smaller cube is 726 square centimeters. Next, let's calculate the surface area of the larger cube. This time, s will equal 13.
The surface area of the larger cube is 1014 square centimeters. Finally, we will calculate the area of the smaller cube's base, which is a square with the side length of 11 centimeters.
We can do this by squaring the side length of 11 centimeters. \begin{gathered} A_\text{square}={\color{#0000FF}{11}}^2={\color{#FF0000}{121}}\text{ cm}^2 \end{gathered} Now we can calculate the total surface area of the figure, which is the surface area of the smaller cube plus the surface area of the larger cube minus twice the area of the smaller cube's base. \begin{gathered} S_\text{figure} = {\color{#A800DD}{726}} + {\color{#FF00FF}{1014}} - 2 \times{\color{#FF0000}{121}} = 1498\text{ cm}^2 \end{gathered} The total surface area of the figure to be painted is 1498 square centimeters.
We are given the dimensions of the school locker in a shape of a rectangular prism.
We want to determine how much the surface area of the locker increase if the height of the locker were increased by 2 inches. To do so, we can calculate the surface area of the locker both before and after increasing the height.
Remember that surface area is the total area of all the surfaces of a three-dimensional figure. Let's begin by recalling the formula for the surface area of a rectangular prism. S=2(wl+hl+wh) We can substitute w= 12, l= 14, and h= 26 into the formula and evaluate S. Let's do it!
We found that the surface area of the original locker is 1688 square inches.
The height of the locker increases by 2 inches. Let's add 2 to the initial height to find the new one. h=26+2=28inches Now we can substitute w= 12, l= 14, and h= 28 into the surface area formula to find the surface area of the taller locker.
The surface area of the taller locker is 1792 square inches.
Finally, we will find the difference between the increased surface area and the original surface area. 1792-1688=104 in^2 Therefore, the surface area of the locker increased by 104 square inches.
We are asked to find the decrease in volume of the locker after the decrease in its length. Let's begin by remembering the formula for the volume of a rectangular prism. V=wl h We can find the original volume of the locker by substituting w= 12, l= 14, and h= 26 into the formula. After the length of the locker is decreased, the new length would be 14-2= 12 inches. Let's use these values to find both the original and decreased volumes.
| Original Locker | Shallower Locker | |
|---|---|---|
| Dimensions | w= 12, l= 14, h= 26 | w= 12, l= 12, h= 26 |
| Substitute | V_\text{or}=({\color{#0000FF}{12}})({\color{#009600}{14}})({\color{#A800DD}{26}}) | V_\text{dec}=({\color{#0000FF}{12}})({\color{#FD9000}{12}})({\color{#A800DD}{26}}) |
| Multiply | V_\text{or}=4368 | V_\text{dec}=3744 |
Now that we know both volumes, we can calculate their difference. 4368-3744=624in^3 Therefore, the volume of the locker would decrease by 624 cubic inches.