The is the sum of the and the combined of the two identical bases. S=Ph+2B
Since the base of a cube is a with a side length s, its area is equal to the of s.
B=s^2
The of the square base can be calculated as the of 4 and s.
P=4s
Finally, the height of the cube is also equal to the side length s. h=s
Now these values will be substituted into the and the resulting equation simplified.
SA= P h+2 B
SA= 4s( s)+2 s^2
SA=4s^2+2s^2
SA=6s^2
