Solving Literal Equations

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Algebra 1

One-Variable Equations

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Solving Literal Equations 1.11 - Solution

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a

Solving the formula for $m$ with inverse operations.

$d=\dfrac{m}{V}$

MultEqn$\text{LHS} \cdot V=\text{RHS}\cdot V$

$dV=m$

RearrangeEqnRearrange equation

$m=dV$

b

The density $d$ is $5.23$ $\text{g}/\text{cm}^3$ and the volume is $V= 1.1$ $\text{cm}^3$. In order to find the mass, $m,$ we substitute these values into our rewritten equation.

$m=dV$

SubstituteII$d={\color{#0000FF}{5.23}}$, $V={\color{#009600}{1.1}}$

$m={\color{#0000FF}{5.23}} \cdot {\color{#009600}{1.1}}$

MultiplyMultiply

$m=5.753$

RoundDecRound to ${\textstyle 2 \, \ifnumequal{2}{1}{\text{decimal}}{\text{decimals}}}$

$m\approx5.75$

Therefore, the mass is approximately $5.75$ g.