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Here are a few recommended readings before getting started with this lesson.
Vincenzo is getting ready to drive home from vacation at the beach. He is sure that if he drives at 50 miles per hour, he will be home in 40 to 55 minutes.
Combining two or more inequalities with the word and
or or
yields what is called a compound inequality.
Compound Inequality | Is Read As |
---|---|
x < 5 or x > 8 | x is less than 5 or greater than 8. |
x > 2 and x ≤ 4 | x is greater than 2 and less than or equal to 4. |
Compound inequalities using the word and
are commonly written without showing the actual word. Consider the following example.
x > 2 and x ≤ 4
The first inequality can be rewritten as 2 < x because the statement x is greater than 2
is equivalent to 2 is less than x.
With this change, the inequality can be rewritten as follows.
2 < x and x ≤ 4 ⇒ 2 < x ≤ 4
and.
Before a compound inequality can be solved, each individual inequality has to be identified. - 3 < 2x - 1 ≤ 2 ⇓ - 3 < 2x - 1 and 2x - 1 ≤ 2
Lastly, combining the two solution sets yields the solution set of the compound inequality. Here, the compound inequality was written in the condensed form of an and
inequality. Therefore, the two solution sets can written separately with the word and,
or they can be combined as follows.
- 1 < x and x ≤ 32 ⇓ - 1 < x ≤ 3/2
or,a solution of either individual inequality is a solution of the compound inequality. Consider the following compound inequality. x ≥ 2 or x < - 2 The graph of this compound inequality is the union of the graphs of the individual inequalities. These graphs are recognized by the fact that they continue infinitely in either direction.
and,however, must be a solution of both individual inequalities. Consider the following inequality. x < 1 and x ≥ - 3 The graph of the compound inequality is the intersection of the graphs of the individual inequalities.
or,compound inequalities written with
anddo not always extend infinitely.
Kevin's class is having a work experience internship this week. He is working with a farmer to test the speed of an autonomous tractor in a field.
In the first test, the tractor started from a point 2 miles away from the barn. After a half hour, the tractor was at least 10 miles away from the barn. In the next test, the tractor started at a point 1.5 miles away from the barn. When it stopped 45 minutes later, it was less than 20 miles from the barn.
and.0.5r + 2 ≥ 10 and 0.75r + 1.5 < 20 To solve this compound inequality, the properties of inequalities will be used. To solve the inequality on the left, first 2 will be subtracted from both sides of the inequality. Similarly, to solve the inequality on the right, 1.5 will be subtracted from both sides of the inequality.
andcan be rewritten as follows. 16 ≤ r < 24.7 This means that the possible speeds of the tractor are greater than or equal to 16 miles per hour and less than 24.7 miles per hour.
On this case, since the inequality is strict, the solution set of the inequality r < 24.7 is made of the numbers to the left of 24.7. Since 24.7 is not included in the solution set, an open circle is used instead.
Since the compound inequality is written with and,
its solution set is made of the numbers that satisfy both inequalities.
Ignacio is interning at the local disaster preparedness center. He is using a simulator to help to secure the unsafe area near a volcano that is about to erupt. He is in charge of marking safe distances to the east and the west of the volcano. He initially marked the safe distance with flags, one 30 miles to the east of the base of the volcano and the other 15 miles to the west.
As time passes and data comes in, Ignacio realizes that his estimates were wrong. He notes that the flag to the west is less than half the distance away from the volcano that it should be. On the other hand, he calculates that the eastern flag covers less than two thirds of the actual necessary safe distance from the volcano.
LHS* 3/2 < RHS * 3/2
a/b* b/a=1
a/c* b = a* b/c
Multiply
Calculate quotient
Rearrange inequality
or.d < -30 or d > 45
Similarly, the graph of the solution set of d > 45 is made of every number to the right of 45, not including 45.
Finally, since it is written with or,
the graph of the compound inequality is the combination of both solution sets and does not need to be adjusted or limited.
Tearrik is spending his week of work experience at a local bakery. On his first day, he bought 100 cookies at a discount. He decides to eat 5 cookies a day until they are all gone. Tearrik is also allowed to bring home 3 cookies per day, which he gives to his brother. Tearrik's brother decides that he will not eat his cookies until he has at least 90 saved up.
and.100-5d>0 and 3d ≥ 90 To solve this compound inequality, both inequalities must be solved. First, to solve the inequality on the left, 100 will be subtracted from both sides of the inequality.
Similarly, the solution set of the inequality d ≥ 30 is made of the numbers greater than or equal to 30. Since thi inequality is not strict, the circle is closed.
The solution set of the compound inequality is made of the numbers that satisfy both inequalities at the same time. Since there are no such numbers, the compound inequality has no solution.
This confirms that the brothers will not eat cookies together.
For his internship, Davontay is working in a research lab. He is researching what tools are used to measure really low and really high temperatures. He found out that a thermocouple thermometer can measure temperatures lower than 3272^(∘) F, while a pyrometer thermometer can measure temperatures greater than or equal to 973 K.
To help find these temperatures in degrees Celsius, the relationships between the different temperature scales are shown in the following table. It should be noted that C refers to a temperature in degrees Celsius, F is the temperature in degrees Fahrenheit, and K refers to kelvins.
Fahrenheit | Kelvin |
---|---|
9/5C + 32 = F | C + 273 = K |
or.9/5C + 32 < 3272 or C + 273 ≥ 973 Now, to solve this compound inequality, each inequality will be solved individually using the Properties of Inequalities. To solve the inequality on the left, first subtract 32 from both sides of the inequality.
LHS-32
LHS* 5/9 < RHS * 5/9
a/c* b = a* b/c
Multiply
Calculate quotient
Similarly, the solution set of the inequality C ≥ 700 is made of every point to the right of 700, including 700.
Since the inequality is written with or,
the solution set of the compound inequality is made of the numbers that satisfy either inequality. By combining the graphs it can be noted that every number is a solution to the compound inequality.
This means that any temperature can be measured using either of the thermometers.
Diego is helping at a local car dealership for his work experience. After spending time at the dealership, he decides to start saving money to buy a car. His father told him that he would double the amount of money that Diego saves, starting from now. Also, Diego will receive extra 500 dollars from his uncle to help buy the car when he finishes saving.
When looking for prices, Diego notices that most of the cars he likes range from 15 thousand dollars to 18 thousand dollars.
2m
Also, Diego's uncle will give Diego $500 dollars after finishing saving. This adds 500 to the amount after it is multiplied by 2. With this information, it is possible to write Diego's total amount of money as an expression.
2m + 500
Diego needs from 15 thousand dollars to 18 thousand dollars to afford a car he likes. Therefore, the total amount of money that Diego needs must lie between these values in order for him to be able to afford the car. This can be expressed as a compound inequality.
2m + 500 ≥ 15 000 and 2m + 500 ≤ 18 000
Since the inequalities are written with and,
they can be rewritten as follows.
15 000 ≤ 2m + 500 ≤ 18 000
Similarly, the graph of the solution set of inequality m≤ 8750 is made of all the points to the left of 8750, including 8750.
Finally, the solution set of the compound inequality is made of every number that both graphs share. In this case, the overlapping space from 7250 to 8750, inclusive.
Various different compound inequalities will be shown in the applet below. Select the correct solution set.
At the beginning of the lesson, it was asked how far Vincenzo's house was from the beach. The following information was given.
Then, the following questions were asked.
and.d/50 ≥ 2/3 and d/50 ≤ 11/12 Recall that compound inequalities written with
andcan be rewritten as follows. 2/3 ≤ d/50 ≤ 11/12 Finally, to find the possible values of d, each section of the compound inequality is multiplied by 50.
Round to 1 decimal place(s)
33.3 ≤ d ≤ 45.8
This compound inequality can be written with the word and.
d ≥ 33.3 and d ≤ 45.8
The values of y are the values that fall outside of this compound inequality, so each individual inequality should be reversed. Note that because 33.3 and 45.8 are included in the original interval, these values cannot be included in the solution set for y. Since d is greater than or equal to 33.3 miles, then y must be less than 33.3 miles.
y < 33.3
Similarly, since the values of d are less than or equal to 45.8 miles, y has to be greater than 45.8 miles.
y > 45.8
The possible values of y are those that are either less than 33.3 or greater than 45.8. Therefore, the compound inequality is written with or.
y < 33.3 or y > 45.8
The solution set of this compound inequality is made of every number left of 33.3 and right of 45.8.