Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
3. Proving Triangles Similar
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Exercise 27 Page 457

Look for corresponding angles of similar triangles.

See solution.

Practice makes perfect

In the given diagram, we are told that PQ is perpendicular to QT, that ST is perpendicular to TQ, and that PQST= QRTV. We want to prove that △ VKR is an isosceles triangle. Let's highlight triangles △ PQR and △ STV on the diagram.

As a first step, we will start by proving that △ PQR and △ STV are similar triangles. Let's investigate the given information.
  • Since PQ ⊥ QT and ST ⊥ TV, we know that ∠ PQR and ∠ STV are right angles. Because all right angles are congruent, we can say that ∠ PQR ≅ ∠ STV. Moreover PQ and ST are the heights of the triangles, and QR and TV are their bases.
  • It is given that the ratios PQ:ST and QR:TV are equal. Therefore, the heights and the bases of triangles △ PQR and △ STV are proportional.

We know that △ PQR and △ STV have two proportional sides and a congruent included angle. By the Side-Angle-Side Similarity Theorem, triangles △ PQR and △ STV are similar. Since corresponding angles in similar triangles are congruent, we know that ∠ PRQ≅ ∠ SVT.

These are angles of triangle △ VKR.

By the Converse of the Isosceles Triangle Theorem, this means that KV ≅ KR. Therefore, △ VKR is isosceles. We can summarize the steps above in a flow proof.