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Pearson Geometry Common Core, 2011

PG

Pearson Geometry Common Core, 2011 View details

9. Proofs Using Coordinate Geometry

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Exercise 37 Page 418

Remember to consider the positive and negative solutions.

12 and - 12

Practice makes perfect

We will solve the given equation by taking the square roots. Remember to consider the positive and negative solutions.

x^2 = 144

sqrt(LHS)=sqrt(RHS)

sqrt(x^2)=sqrt(144)

sqrt(a^2)=± a

x=±sqrt(144)

Calculate root

x=± 12

We found that x=± 12. Thus, there are two solutions for the equation, which are x= 12 and x= - 12.

Checking Our Answer

Checking our answer

We can check our answers by substituting them for x in the given equation. Let's start with x=- 12.

x^2=144

x= - 12

( - 12)^2? =144

▼

Simplify

NegBaseToPosPow

(- a)^2 = a^2

12^2? =144

Calculate power

144=144 ✓

Since 144=144, we know that x=- 12 is a solution of the equation. Let's check if x=12 is also a solution.

x^2=144

x= 12

12 ^2? =144

Calculate power

144=144 ✓

Again, since 144=144, we know that x=12 is a solution of the equation.

Subchapter links

Lesson Check p.416

Standardized Test Prep p.418

Mixed Review p.418