Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
3. Proving Lines Parallel
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Exercise 31 Page 162

x=10
m∠1=70
m∠2=70

Practice makes perfect

We want to determine the value of x for the given measures of angles for which r∥ s. In this case, we have been given expressions to represent the measures of ∠ 1 and ∠ 2. m∠1&= 80-x m∠2&= 90-2x Let's add these angle measures to the given figure so that we can get a better idea of their relationship.

We can see that (80-x)^(∘) and (90-2x)^(∘) are corresponding angles. Because we want to determine the measures of the angles for which the lines r and s will be parallel, we will use the Converse of the Corresponding Angles Theorem to determine x.

Converse of the Corresponding Angles Theorem

If two lines and a transversal form corresponding angles that are congruent, then the lines are parallel.

We can visualize this theorem. Consider two lines l and m. These lines are parallel if one of the following pairs of angles form a pair of corresponding congruent angles.

Applying the theorem, we can create an equation using the fact that the corresponding angles must be congruent for the lines r and s to be parallel. (80-x)^(∘)= (90-2x)^(∘) Let's solve the equation for x.
80-x=90-2x
80+x=90
x=10
Finally, we can use the fact that x=10 to determine the measures of ∠1 and ∠2. m∠1&=80- 10=70 m∠2&=90-2( 10)=70 For x=10 we have that r ∥ s, m ∠ 1 = 70, and m ∠ 2 = 70.