body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Pearson Geometry Common Core, 2011

PG

Pearson Geometry Common Core, 2011 View details

3. Proving Lines Parallel

Continue to next subchapter

Exercise 15 Page 161

Use the Converse of the Alternate Exterior Angles Theorem.

x=59

Practice makes perfect

Both of the given angles are on the outer part of the potential parallel lines, and are on opposite sides of the transversal. Therefore, the angles can be classified as alternate exterior angles. According to the Converse of the Alternate Exterior Angles Theorem, if the angles are congruent, the lines are parallel.

If the angles are congruent, they have the same measure. 3x-33=2x+26 Let's solve this equation.

3x-33=2x+26

LHS+33=RHS+33

3x=2x+59

LHS-2x=RHS-2x

x = 59

When x=59, the angles are congruent. Therefore, for x=59, we have that m ∥ l.

Subchapter links

Lesson Check p.160

Practice and Problem-Solving Exercises p.160-162

Standardized Test Prep p.163

Mixed Review p.163