Pearson Geometry Common Core, 2011
PG
Pearson Geometry Common Core, 2011 View details
Mid-Chapter Quiz
Continue to next subchapter

Exercise 7 Page 716

Use the formula for the surface area of a pyramid.

9600 m^2

Practice makes perfect

We are given the following pyramid and we want to find its surface area.

To calculate the surface area of a pyramid, we can use the following formula, where P is the perimeter of the base, l is the slant height, and B is the area of the base. S=1/2Pl+BThe base of the pyramid is a square with the side length s of 60meters. Let's calculate its perimeter P! P=4( 60) ⇒ P=240m The area of the square equals the squared length of the side. B= 60^2 ⇒ B=3600m^2 To find the slant height, we can use the Pythagorean Theorem, where the slant height l is the hypotenuse. The height and apothem of the pyramid are the legs of the triangle. Remember that the apothem is half of the pyramid's side length. 60m/2 = 30m Let's use these given values to solve for l.
a^2+h^2=l^2
30^2+ 40^2=l^2
â–Ľ
Solve for l
900+1600=l^2
2500=l^2
l^2=2500
l=sqrt(2500)
l=50
Note that, when solving the above equation, we kept the principal root. This is because l is the slant height of the pyramid and therefore it must be positive. Let's substitute all of these values into the formula for the surface area and calculate it.
S=1/2Pl+B
S=1/2(240)(50)+3600
â–Ľ
Simplify right-hand side
S=1/2(12 000)+3600
S=12 000/2+3600
S=6000+3600
S=9600
The surface area of the pyramid is 9600m^2.