Pearson Geometry Common Core, 2011
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Pearson Geometry Common Core, 2011 View details
Mid-Chapter Quiz
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Exercise 19 Page 716

Use the formula for the surface area of a cone.

141cm^2

Practice makes perfect

Let's consider the given 3-D figure.

The given solid is a cone. To calculate the surface area of a cone, we can use the known formula where r is the radius of the base and l is the slant height of the cone. S=π rl+π r^2 From the diagram, we know that the diameter of the cone's base is 8centimeters. By dividing it by 2, we get the radius of the base. r=8/2 ⇔ r= 4cm To find the slant height, we can use the Pythagorean Theorem. Therefore, the slant height l is the hypotenuse. The height and radius of the cone are the legs. Let's use these given values to solve for l.
r^2+h^2=l^2
4^2+ 6^2=l^2
Solve for l
16+36=l^2
52=l^2
l^2=52
l=sqrt(52)
l=7.211102...
l ≈ 7.2
Therefore, the slant height of the cone is about 7.2cm. Note that, when solving the above equation, we kept the principal root. This is because l must be positive. By substituting r for 4 and l for 7.2 into the formula, we can calculate S.
S=π rl+π r^2
S=π( 4)( 7.2)+π( 4)^2
Simplify right-hand side
S=π(4)(7.2)+16π
S=28.8π+16π
S=44.8π
S=140.743350...
S≈ 141
The surface area of the cone is approximately 141cm^2.