Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
8. Systems of Linear and Quadratic Equations
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Exercise 6 Page 599

Practice makes perfect
a To write a system of linear and quadratic equations with two solutions, we need to write the equation of a parabola and a line that havstwo points of intersection. To keep it simple we will consider the graph of the quadratic function y=x^2.

Any horizontal line above the x-axis will intersect this parabola twice. For example, let's consider the line y=1.

We can see that the line and the parabola have two points of intersection. Therefore, the system formed by the equations of the above graphs will have two solutions. y=x^2 y=1 Note that there are infinitely many systems that satisfy the given condition. This is only one of them.

b Just as we did in Part A, we will consider the graph of the quadratic function y=x^2.

Note that the above parabola intersects the x-axis at exactly one point. The x-axis can be thought of as the line y=0.

Therefore, the system formed by the equations of the above graphs will have exactly one solution. y=x^2 y=0 Note that there are infinitely many systems that satisfy the given condition. This is only one of them.

c One last time, we will consider the graph of y=x^2.

No horizontal line below the x-axis will intersect this parabola. As an example, let's consider the line y=- 1.

We can see that the line and the parabola do not intersect. Therefore, the system formed by the equations of the above graphs will have no solutions. y=x^2 y=- 1 Note that there are infinitely many systems that satisfy the given condition. This is only one of them.