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Pearson Algebra 1 Common Core, 2011

PA

Pearson Algebra 1 Common Core, 2011 View details

1. Quadratic Graphs and Their Properties

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Exercise 53 Page 552

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side.

F

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality. In this case, we need to start by using the Distributive Property to simplify the left-hand side of the equation.

2(x+3)+7=- 11

Distribute 2

2* x+2* 3+7=- 11

Multiply

2x+6+7=- 11

Add terms

2x+13=- 11

Now, we can continue to solve using the Properties of Equality.

2x+13= -11

LHS-13=RHS-13

2x+13-13=- 11-13

Subtract term

2x=- 24

.LHS /2.=.RHS /2.

2/2x=- 24/2

Calculate quotient

x=- 12

The solution to the equation is x=- 12, so the correct answer is F.

Subchapter links

Lesson Check p.549

Practice and Problem-Solving Exercises p.550-552

Standardized Test Prep p.552

Mixed Review p.552