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We want to compare when each graph is positive or negative. Recall that terms that are squared are always positive.
We can determine the width of parabolas from the |a|-value of the equation.
a>0
|a|>1
We will be comparing Equation One, y_1=ax^2, and Equation Two, y_2=a^2x^2. Equation One:& y_1=ax^2 Equation Two:& y_2=a^2x^2 The difference between the equations is that in Equation Two, it is a^2 instead of just a. Recall that when we square a number, the result is always positive. Therefore, Equation Two will be always be positive, regardless of the a-value, because we are multiplying two positive numbers. Ifa is positive or negative: y_2=a^2x^2 ⇒ y_2=(+)(+) ⇒ y_2=(+) In Equation One, if a is positive we will multiply two positive numbers together, resulting in the function being positive. Ifa is positive: y_1=ax^2 ⇒ y_1=(+)(+) ⇒ y_1=(+) However, when a is negative we will be multiplying a negative value by the always-positive x^2 value. Therefore, when a is negative, the function will be negative. Ifa is negative: y_1=ax^2 ⇒ y_1=(-)(+) ⇒ y_1=(-) In conclusion, this all tells us that when a is positive, both Equation One and Two will be positive. However, when a is negative Equation One will be negative and Equation Two will be positive. Thus, the graphs will be in the same quadrant when a is positive.
|a| | a^2 |
---|---|
2 | 4 |
3 | 9 |
4 | 16 |
We can see that when |a| is greater than one, |a|less than or equal to one and greater than zero. That is, 0<|a|≤ 1. Let's test some values to see what happens.
|a| | a^2 |
---|---|
1 | 1^2=1 |
1/2 | 1^2/2^2=1/4 |
1/4 | 1^2/4^2=1/16 |
We see that when 0<|a|≤ 1, |a| is not less than than a^2. Therefore, this will not be part of our solution. |a|1 In summation, we have found that |a|1. This means that the graph of y_1=ax^2 will be wider than y_2=a^2x^2 when |a|>1.