Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
6. Exponential Functions
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Exercise 39 Page 457

Substitute -2, -1, 0, 1, 2 and 3 for x.

{1111.11,333.33,100,30,9,2.7}, decrease

Practice makes perfect
We are given an equation and asked to evaluate it for some given values. x=-2, -1, 0, 1, 2, 3This means that we should substitute -2, -1, 0, 1, 2, and 3 for x in the given equation and then evaluate. Let's start with -2.
y = 100*0.3^x
y = 100*0.3^(-2)
â–Ľ
Evaluate right-hand side
y = 100*(3/10)^(-2)
y = 100 * 3^(-2)/10^(-2)
y = 100 * 1/10^(-2) * 3^(-2)
y = 100 * 1/1/10^2 * 1/3^2
y = 100 * 10^2/1 * 1/3^2
y = 100 * 100/1 * 1/9
y = 10 000/1* 1/9
y = 10 000/9
y = 1111.11
Now, let's do the same thing for the rest of the values.
x Evaluation Result
-2 100 * 0.3^(-2) 1111.11
-1 100 * 0.3^(-1) 333.33
0 100 * 0.3^0 100
1 100 * 0.3^1 30
2 100 * 0.3^2 9
3 100 * 0.3^3 2.7

As we see, the values of the range decreases.