Pearson Algebra 1 Common Core, 2011
PA
Pearson Algebra 1 Common Core, 2011 View details
6. Exponential Functions
Continue to next subchapter

Exercise 32 Page 457

Substitute -2, -1, 0, 1, 2 and 3 for x.

{0.04,0.2,1,5,25,125}, increase

Practice makes perfect
We are given an equation and asked to evaluate it for some given values. x=-2, -1, 0, 1, 2, 3This means that we should substitute -2, -1, 0, 1, 2, and 3 for x in the given equation and then evaluate. Let's start with -2.
f(x) = 5^x
f( -2) = 5^(-2)
f(-2) = 1/5^2
f(-2) = 1/25
â–Ľ
Write as a decimal
f(-2) = 1*4/25*4
f(-2) = 4/100
f(-2) = 0.04
Now, let's do the same thing for the rest of the values.
x Evaluation Result
-2 5^(-2) 0.04
-1 5^(-1) 0.2
0 5^0 1
1 5^1 5
2 5^2 25
3 5^3 125

As we see, the values of the range increases.