body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

Pearson Algebra 1 Common Core, 2011

PA

Pearson Algebra 1 Common Core, 2011 View details

6. Exponential Functions

Continue to next subchapter

Exercise 34 Page 457

Substitute -2, -1, 0, 1, 2 and 3 for x.

{100,10,1,0.1,0.01,0.001}, decrease

Practice makes perfect

We are given an equation and asked to evaluate it for some given values. x=-2, -1, 0, 1, 2, 3This means that we should substitute -2, -1, 0, 1, 2, and 3 for x in the given equation and then evaluate. Let's start with -2.

h(x) = 0.1^x

x= -2

h( -2) = 0.1^(-2)

Write as a fraction

h(-2) = (1/10)^(-2)

(a/b)^m=a^m/b^m

h(-2) = 1^(-2)/10^(-2)

1^a=1

h(-2) = 1/10^(-2)

NegExponentToFrac

a^(- m)=1/a^m

h(-2) = 1/1/10^2

a/b/c= a * c/b

h(-2) = 1*10^2/1

Calculate power

h(-2) = 1*100/1

Identity Property of Multiplication

h(-2) = 100/1

a/1=a

h(-2) = 100

Now, let's do the same thing for the rest of the values.

x	Evaluation	Result
-2	0.1^(-2)	100
-1	0.1^(-1)	10
0	0.1^0	1
1	0.1^1	0.1
2	0.1^2	0.01
3	0.1^3	0.001

As we see, the values of the range decreases.

Subchapter links

Lesson Check p.456

Practice and Problem-Solving Exercises p.457-459

Standardized Test Prep p.459

Mixed Review p.459