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Pearson Algebra 1 Common Core, 2011

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Pearson Algebra 1 Common Core, 2011 View details

Mid-Chapter Quiz

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Exercise 17 Page 632

The Multiplication Property of Square Roots tells us that sqrt(ab)=sqrt(a) * sqrt(b), for a≥ 0 and b≥ 0.

- 1/3c

Practice makes perfect

We want to simplify a radical expression. To do so we will assume that c>0, otherwise the given expression would not be defined. - sqrt(5c)sqrt(45c^3)Let's recall the Multiplication Property of Square Roots. sqrt(ab)=sqrt(a) * sqrt(b), for a≥ 0,b≥ 0 We can use this property for our expression.

- sqrt(5c)/sqrt(45c^3)

SplitIntoFactors

Split into factors

- sqrt(5* c)/sqrt(9* 5* c^2* c)

CommutativePropMult

Commutative Property of Multiplication

- sqrt(5* c)/sqrt(9* c^2* 5* c)

sqrt(a* b)=sqrt(a)*sqrt(b)

- sqrt(5* c)/sqrt(9* c^2)* sqrt(5* c)

Write as a product of fractions

- 1/sqrt(9* c^2)* sqrt(5* c)/sqrt(5* c)

a/a=1

- 1/sqrt(9* c^2)* 1

Identity Property of Multiplication

- 1/sqrt(9 * c^2)

▼

Simplify denominator

sqrt(a* b)=sqrt(a)*sqrt(b)

- 1/sqrt(9)sqrt(c^2)

Calculate root

- 1/3sqrt(c^2)

SqrtPowToNumber

sqrt(a^2)=a

- 1/3c