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Use the fact that conjugates are the sum and difference of the same two terms.
See solution.
Let's start by considering a few examples of fractions with radical expressions in their denominators.
2/sqrt(3), 18/9-sqrt(5), 8/sqrt(7)+sqrt(2)
The first expression has only one term in the denominator. Therefore, we can rationalize its denominator by multiplying this expression by sqrt(3)sqrt(3).
2/sqrt(3)* sqrt(3)/sqrt(3)=2sqrt(3)/3
| Fraction | 18/9-sqrt(5) | 8/sqrt(7)+sqrt(2) |
|---|---|---|
| Denominator | 9- sqrt(5) | sqrt(7)+ sqrt(2) |
| Conjugate | 9+ sqrt(5) | sqrt(7)- sqrt(2) |
The product of conjugates is a difference of squares of the terms. Product: (a+b)(a-b)= a^2- b^2 Let's multiply each expression by the corresponding fraction and simplify.
| Multiplication by the Expression | 18/9-sqrt(5)* 9+sqrt(5)/9+sqrt(5) | 8/sqrt(7)+sqrt(2)* sqrt(7)-sqrt(2)/sqrt(7)-sqrt(2) |
|---|---|---|
| Product of Conjugates | 18(9+sqrt(5))/9^2-(sqrt(5))^2 | 8(sqrt(7)-sqrt(2))/(sqrt(7))^2-(sqrt(2))^2 |
| Simplification | 18(9+sqrt(5))/76 | 8(sqrt(7)-sqrt(2))/47 |
As we can see, the denominators are now rational values, so we reached our goal. We can conclude that conjugates are used to rationalize denominators that have two terms. When multiplying conjugates, we get the difference of two squares which eliminates the radicals.