Pearson Algebra 1 Common Core, 2011
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Pearson Algebra 1 Common Core, 2011 View details
Mid-Chapter Quiz
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Exercise 19 Page 632

The Multiplication Property of Square Roots tells us that sqrt(ab)=sqrt(a) * sqrt(b), for a≥ 0 and b≥ 0.

sqrt(65f)/5

Practice makes perfect
We want to simplify a radical expression. To do so we will assume that f>0, otherwise the given expression would not be defined. sqrt(13f^3)/sqrt(5f^2) Let's recall the Multiplication Property of Square Roots. sqrt(ab)=sqrt(a) * sqrt(b),fora≥ 0,b≥ 0. We can use this property for our expression.
sqrt(13f^3)/sqrt(5f^2)
sqrt(13f* f^2)/sqrt(5* f^2)
sqrt(13f)* sqrt(f^2)/sqrt(5)* sqrt(f^2)
â–Ľ
Simplify
sqrt(13f)* f/sqrt(5)* f
sqrt(13f)/sqrt(5)
Now that we have simplified the factors as much as possible, we need to rationalize the denominator. To do this, we will multiply the numerator and denominator by a square root that will eliminate the radical in the denominator.
sqrt(13f)/sqrt(5)
sqrt(13f)* sqrt(5)/sqrt(5)* sqrt(5)
sqrt(65f)/sqrt(5)* sqrt(5)
sqrt(65f)/5