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| | 12 Theory slides |
| | 10 Exercises - Grade E - A |
| | Each lesson is meant to take 1-2 classroom sessions |
Multiplying a positive integer a by a positive integer b is the same as adding b to itself a times.
Multiplication is the same as repeated addition. However, when multiplying integers, the signs of the factors determine whether the product is positive or negative.
The product of two integers is always positive if and only if the factors have the same sign. This means that when the factors are both positive or both negative, ignore the signs and multiply them as if they were whole numbers. To illustrate this process, consider the following multiplication of integers. -3*(-4) There are two steps to follow when the factors have the same sign.
The endpoint represents the product of the given multiplication of integers with the same sign. 3*4=12 ⇔ -3*(-4)=12 The result of multiplication of integers with the same sign is always positive.
The product of two integers is always negative if and only if one factor is negative and the other is positive. Change the negative factor to its opposite and perform the multiplication as if both were whole numbers. Next, change the result to its opposite to get the final product. Consider the following multiplication of integers. -7*2 Follow these three steps to find the product of two integers with different signs.
The endpoint is the product of the resulting multiplication. This means that 7*2=14.
LaShay is a brilliant pianist. One day, she is asked to play at her school concert. She is excited to showcase her talent in front of her peers. She now wants to calculate how long it would take her to play her piece.
She has a total of 8 songs to play and each song is an average of 3 minutes long. How long would it take her to play all the songs?
The endpoint is 24. This is the product of 8*3. This means that it will take LaShay 24 minutes to play her 8 pieces. Total Time= 8* 3 ⇓ Total Time=24
In the afternoons, LaShay takes a break from her studies and piano lessons to help her aunt with her pizza shop.
LaShay's aunt pays her $10 for each day she helps her. However, every time LaShay is late, she loses $3.
Next, remember that she was late 6 out of the 15 days she helped her aunt last month. The amount she lost last month is given by multiplying the number of days she was late by the amount she lost each day for being late. Total Amount Lost Last Month 6* (-3) This situation is a multiplication of a positive integer by a negative integer. Recall that the result is negative when multiplying two integers with different signs. With this in mind, perform the multiplication as if both were whole numbers by ignoring their signs. 6* (-3) ⇒ 6* 3 The resulting multiplication indicates 6 equal intervals of 3. A number line can be used to help find this product.
This is a multiplication of two positive integers, so the result is also positive. Because the integers are two-digit numbers, use the multiplication digit by digit to find their product.
The division of integer numbers is similar to the division of whole numbers. However, when dividing integers, the signs of the dividend and the divisor determine whether the quotient is positive or negative.
The quotient of dividing an integer a by an integer b is always positive if those integers have the same sign. This means the dividend and the divisor are both negative or both positive. If this condition is met, ignore their signs and perform the division as if they were whole numbers. This will be illustrated using the following division of integers. -15÷(-3) Follow these two steps when dividing two integers with the same sign.
It took 5 jumps of 3 units to reach 15. This means that the quotient of the initial division is 5. 15÷ 3=5 ⇔ -15÷(-3)=5 The quotient of two numbers with the same sign is always positive.
The quotient of dividing two integers is always negative if and only if one is negative and the other is positive. Change the negative number to its opposite and perform the division as if they were whole numbers. Next, change the result to its opposite to get the quotient of the initial division. This process will be illustrated with the following division. -12÷4 There are three steps to follow to find the quotient when dividing two numbers with different signs.
It took three jumps of 4 units to reach 12. This means that 12÷4=3.
LaShay wants to buy a new dress for her upcoming performance with her earnings for helping her aunt at the pizza shop. She and her parents are at the shopping center. They must take the elevator to the sixth floor to get to LaShay's favorite clothing store.
They are at the end of a line of 35 people waiting for the elevator. The elevator can only carry seven people at a time. How many elevator trips will it take for LaShay and her parents to get into the elevator?
Since it takes 5 jumps of 7 to reach 35, 35÷ 7=5. Now, recall that LaShay and her family are at the end of the line. This means that it will take 5 elevator trips until they get into the elevator. LaShay cannot wait to get her new dress!
LaShay's concert went so well that she decided to play one of her favorite pieces for an upcoming competition.
She made 6 mistakes while playing for the competition and lost -96 points. If each mistake was worth the same number of points, how much was each mistake worth? Give the answer as a negative integer.
The quotient is 16. However, to get the result of the original division, remember to change 16 to its opposite, -16. 96÷ 6= 16 ⇒ -96÷ 6= -16 This means that LaShay lost 16 points for each mistake made. This did not stop her, though — she took the competition by storm with her incredible talent!
Negative numbers have a 2000-year history. As early as the 7^(th) century, Brahmagupta established the initial rules for handling negative numbers. However, it was not until the 16^(th) that negative numbers were used to solve equations.
Consider the given multiplication. -10*-1 We can see that this is a multiplication of two negative integers. Recall that the result is always positive when multiplying two integers with the same sign. We can ignore the signs of the factors for now and perform the multiplication as if both integers were whole numbers. -10*-1 ⇒ 10* 1 Our multiplication simplifies to the multiplication of 10 and 1. We can use the fact that the multiplication of any number and 1 is the number itself to get the product of the multiplication. 10*1=1 ⇒ -10*-1=10
Let's look at the given expression.
-2*12
We have the multiplication of negative 2 by 12. Because both factors have different signs, their product is negative. Let's perform this multiplication as if both numbers were whole numbers and then include the negative sign in the result. We will perform the multiplication using a number line.
We made 2 jumps of 12 units on the number line and ended at 24. This means that 2* 12= 24. We now change this product to its opposite to get the product of the initial multiplication. 2*12=24 ⇒ -2*12=-24
Consider the given multiplication of integers.
13* 15
We have a multiplication of two positive integers, so their product will also be positive. Because both are two-digit numbers, we can use digit by digit multiplication to find their product.
The product of 13 and 15 is 195.
Consider the given division expression. 84÷(-6) The division of two integers with different signs is always negative. We can calculate the quotient by ignoring the signs of the dividend and divisor and perform the division as if both numbers were whole numbers. 84÷(-6) ⇒ 84÷6 We then add the negative sign to the result to get the quotient of the original division of integers. Let's first find the quotient of the whole numbers by using long division.
The quotient is 14. Let's change it to its opposite to get the result of the initial division. 84÷6= 14 ⇒ 84÷(-6)= -14
The given expression is also a division of two integers with different signs.
-16÷4
Let's ignore the signs of the integers and perform the division as if both integers were whole numbers again.
-16÷4 ⇒ 16÷4
The resulting division gives how many intervals of 4 are needed to reach 16 on a number line. Let's find it!
We needed 4 jumps of 4 to reach 16. This means that the result of the division is 4. If we change this number to its opposite -4, we get the result of the initial division of integers with different signs. 16÷ 4= 4 ⇒ - 16÷ 4=- 4
We have now a division of two negative integers.
-38÷(-2)
The result of dividing two integers with the same sign is always positive. With this in mind, we can ignore the signs of the integers in the given division and perform the division as if they were whole numbers.
-38÷(-2) ⇒ 38÷2
Now, we can use long division to find the result of this division.
The quotient of dividing 38 by 2 is 19. 38÷2= 19 ⇒ -38÷(-2)= 19
Which of the following has the same product as 6*10? Select all that apply.
We are asked to determine which of the given options has the same product as 6*10. 6* 10 We have a multiplication of two positive integers, so the product is also positive. Let's use a shortcut to find this product. Because we have a multiplication of an integer by 10, we can add a 0 to the end of the other factor to get the product. 6*10= 6 0 Next, let's find the product of the given options to find which ones are also 60, starting with the first option. 4* 15 We can use digit by digit multiplication to find this product.
The product of 4* 15 is also 60. This means that the expression 4*15 has the same product as 6*10. Let's now find the products of the remaining options using a similar process.
| Expression | Product | Equals 60? |
|---|---|---|
| 4*15 | 60 | ✓ |
| 7*8 | 56 | * |
| 5*12 | 60 | ✓ |
| 2*31 | 62 | * |
We conclude that the expressions 4*15 and 5*12 have the same product as 6*10.
Which of the following division expression has the same quotient as 63÷(- 7)? Select all that apply.
We will begin by finding the quotient of 63÷(-7). Note that this is a division of two integers with different signs. We can calculate this quotient by temporarily ignoring the signs of the values and finding their quotient. 63÷(-7) ⇒ 63÷7 Let's use a number line to find the quotient. In this case, the quotient is the number of jumps of 7 that are needed to reach 63.
The quotient is 9. Remember to change this result to its opposite to get the result of the initial division of integers with different signs. 63÷7= 9 ⇒ 63÷(-7)= -9 We now know that we need to determine which of the given options also has a quotient of -9. Consider the first expression. -36÷ 4 We can see that this quotient will also be negative because we have a division of integers with different signs. Again, we first find the quotient of the numbers without considering their signs. -36÷4 ⇒ 36÷4 Let's use another number line to find the quotient!
The quotient is 9, so we change it to its opposite to find the quotient of the original division expression. 36÷4= 9 ⇒ -36÷4= -9 Let's calculate the quotient of the remaining options by following a similar fashion.
| Option | Quotient | Equals -9? |
|---|---|---|
| -36÷4 | -9 | ✓ |
| 18÷6 | 3 | * |
| 72÷8 | 9 | * |
| 54÷(-6) | -9 | ✓ |
The options with the same quotient as 63÷(-7) are -36÷4 and 54÷(-6).