McGraw Hill Integrated II, 2012
MH
McGraw Hill Integrated II, 2012 View details
6. Similarity Transformations
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Exercise 17 Page 597

Find the lengths of the sides of each triangle.

Graph:

Verification: See solution.

Practice makes perfect

Let's use the given coordinates to draw the original figure and the image of its dilation.

Let's use the coordinates of the vertices to find the lengths of the sides of each triangle.
Side Vertices Distance Formula Simplified
JK ( - 6,8), (6,6) sqrt((6-( -6))^2+(6- 8)^2) 2sqrt(37)
DG ( - 12,16), (12,12) sqrt((12-( - 12))^2+(12- 16)^2) 4sqrt(37)
KL (6,6), ( - 2,4) sqrt(( - 2-6)^2+( 4-6)^2) 2sqrt(17)
GH (12,12), ( - 4,8) sqrt(( - 4-12)^2+( 8-12)^2) 4sqrt(17)
LJ ( - 2,4), ( - 6,8) sqrt(( - 6-( - 2))^2+( 8- 4)^2) 4sqrt(2)
HD ( - 4,8), ( - 12,16) sqrt(( - 12-( - 4))^2+( 16- 8)^2) 8sqrt(2)

Now, we can find the ratios between the corresponding sides. DG/JK=4sqrt(37)/2sqrt(37) = 2 [1.2em] GH/KL=4sqrt(17)/2sqrt(17) = 2 [1.2em] HD/LJ=8sqrt(2)/4sqrt(2) = 2 We can tell that these ratios are equivalent. Therefore, the corresponding side lengths of â–ł JKL and â–ł DGH are proportional. By the Side-Side-Side Similarity Theorem, we can conclude that â–ł JKL is similar to â–ł DGH. â–ł JKL ~ â–ł DGH Therefore, the dilation is a similarity transformation.