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Notice that △ ABC and △ ADE share ∠A.
Graph:
Verification: See solution.
Let's use the given coordinates to draw the original figure and the image of its dilation.
We can see that △ ABC and △ ADE share ∠A, and we know that ∠A ≅ ∠A. Let's use the coordinates of the vertices to find the lengths of the sides of each triangle that include ∠A.
| Side | Vertices | Distance Formula | Simplified |
|---|---|---|---|
| AB | ( 1,3), ( - 1,2) | sqrt(( - 1- 1)^2+( 2- 3)^2) | sqrt(5) |
| AD | ( 1,3), (- 7,- 1) | sqrt((- 7- 1)^2+(- 1- 3)^2) | 4sqrt(5) |
| AC | ( 1,3), ( 1,1) | sqrt(( 1- 1)^2+( 1- 3)^2) | 2 |
| AE | ( 1,3), ( 1,- 5) | sqrt(( 1- 1)^2+( - 5- 3)^2) | 8 |
Now, we can find the ratios between the corresponding sides. AD/AB=4sqrt(5)/sqrt(5) = 4 [1.2em] AE/AC=8/2 = 4 We can tell that these ratios are equivalent. Therefore, the lengths of two sides of â–³ ABC are proportional to the lengths of two corresponding sides of â–³ ADE, and the included angles are congruent. By the Side-Angle-Side Similarity Theorem, we can conclude that â–³ ABC is similar to â–³ ADE. â–³ ABC ~ â–³ ADE Therefore, the dilation is a similarity transformation.