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Notice that △ ABC and △ ADE share ∠A.
See solution.
Let's use the given graph to read the coordinates of the original figure and the image of its dilation.
We can see that △ ABC and △ ADE share ∠A, and we know that ∠A ≅ ∠A. Let's use the coordinates of the vertices to find the lengths of the sides of each triangle that include ∠A.
| Side | Vertices | Distance Formula | Simplified |
|---|---|---|---|
| AD | ( 0,0), ( - 2,- 2) | sqrt(( - 2- 0)^2+( - 2- 0)^2) | 2 * sqrt(2) |
| AB | ( 0,0), (- 4,- 4) | sqrt((- 4- 0)^2+(- 4- 0)^2) | 4 * sqrt(2) |
| AE | ( 0,0), ( 2,- 1) | sqrt(( 2- 0)^2+( - 1- 0)^2) | sqrt(5) |
| AC | ( 0,0), ( 4,- 2) | sqrt(( 4- 0)^2+( - 2- 0)^2) | 2 * sqrt(5) |
Now, we can find the ratios between the corresponding sides. AB/AD=4 * sqrt(2)/2 * sqrt(2) =2 [1.2em] AC/AE=2 * sqrt(5)/sqrt(5) =2 We can tell that these ratios are equivalent. Therefore, the lengths of two sides of â–³ ABC are proportional to the lengths of two corresponding sides of â–³ ADE, and the included angles are congruent. By the Side-Angle-Side Similarity Theorem, we can conclude that â–³ ABC is similar to â–³ ADE. â–³ ABC ~ â–³ ADE Therefore, the dilation is a similarity transformation.