McGraw Hill Integrated II, 2012
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McGraw Hill Integrated II, 2012 View details
6. Similarity Transformations
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Exercise 4 Page 596

Notice that △ ABC and △ ADE share ∠ A.

See solution.

Practice makes perfect

Let's use the given graph to read the coordinates of the original figure and the image of its dilation.

We can see that △ ABC and △ ADE share ∠ A, and we know that ∠ A ≅ ∠ A. Let's use the coordinates of the vertices to find the lengths of the sides of each triangle that include ∠ A.

Side Vertices Distance Formula Simplified
AD ( 0,0), ( - 2,- 2) sqrt(( - 2- 0)^2+( - 2- 0)^2) 2 * sqrt(2)
AB ( 0,0), (- 4,- 4) sqrt((- 4- 0)^2+(- 4- 0)^2) 4 * sqrt(2)
AE ( 0,0), ( 2,- 1) sqrt(( 2- 0)^2+( - 1- 0)^2) sqrt(5)
AC ( 0,0), ( 4,- 2) sqrt(( 4- 0)^2+( - 2- 0)^2) 2 * sqrt(5)

Now, we can find the ratios between the corresponding sides. AB/AD=4 * sqrt(2)/2 * sqrt(2) =2 [1.2em] AC/AE=2 * sqrt(5)/sqrt(5) =2 We can tell that these ratios are equivalent. Therefore, the lengths of two sides of â–³ ABC are proportional to the lengths of two corresponding sides of â–³ ADE, and the included angles are congruent. By the Side-Angle-Side Similarity Theorem, we can conclude that â–³ ABC is similar to â–³ ADE. â–³ ABC ~ â–³ ADE Therefore, the dilation is a similarity transformation.