6. Similarity Transformations
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Notice that △ JRS and △ JKL share ∠ J.
Example Solution: See solution.
Let's use the given graph to read the coordinates of the original figure and the image of its dilation.
| Side | Vertices | Distance Formula | Simplified |
|---|---|---|---|
| JK | ( 0,0), ( - 6,2) | sqrt(( - 6- 0)^2+( 2- 0)^2) | 2 * sqrt(10) |
| JR | ( 0,0), (- 3,1) | sqrt((- 3- 0)^2+(1- 0)^2) | sqrt(10) |
| JL | ( 0,0), ( - 2,6) | sqrt(( - 2- 0)^2+( 6- 0)^2) | 2 * sqrt(10) |
| JS | ( 0,0), ( - 1,3) | sqrt(( - 1- 0)^2+( 3- 0)^2) | sqrt(10) |
Now, we can find the ratios between the corresponding sides. JR/JK=sqrt(10)/2 * sqrt(10) = 1/2 [1.2em] JS/JL=sqrt(10)/2 * sqrt(10) = 1/2 We can tell that these ratios are equivalent. Therefore, the lengths of two sides of △ JRS are proportional to the lengths of two corresponding sides of △ JKL, and the included angles are congruent. By the Side-Angle-Side Similarity Theorem, we can conclude that △ JRS is similar to △ JKL. △ JRS ~ △ JKL Therefore, the dilation is a similarity transformation.