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Start by identifying the hypotenuse of the right triangle. Then find the sides that are opposite and adjacent to each angle.
Ratio for ∠J: sin J =sqrt(3)/2≈ 0.87, cos J=2sqrt(2)/4sqrt(2)=0.50, tan J=2sqrt(6)/2sqrt(2)≈ 1.73
Ratio for ∠L: sin L =2sqrt(2)/4sqrt(2)=0.50, cos L=sqrt(3)/2≈ 0.87, tan L=sqrt(3)/3≈ 0.58
For the given right triangle, we want to write the ratios for the sine, cosine, and tangent of ∠J and ∠L.
Let's start by identifying the hypotenuse of the triangle and the sides that are opposite and adjacent to ∠J.
| Ratio | Definition | Value |
|---|---|---|
| sin J | Length of leg opposite to∠J/Length of hypotenuse | 2sqrt(6)/4sqrt(2)=sqrt(3)/2≈ 0.87 |
| cos J | Length of leg adjacent to∠J/Length of hypotenuse | 2sqrt(2)/4sqrt(2)=0.50 |
| tan J | Length of leg opposite to∠J/Length of leg adjacent to∠J | 2sqrt(6)/2sqrt(2)=sqrt(3)≈ 1.73 |
We already know the length of the hypotenuse is 4sqrt(2). Let's identify the sides that are opposite and adjacent to ∠L.
The length of the side adjacent to ∠L is 2sqrt(6) and the length of the side opposite to ∠L is 2sqrt(2). With this information, we can find the desired ratios.
| Ratio | Definition | Value |
|---|---|---|
| sin L | Length of leg opposite to∠L/Length of hypotenuse | 2sqrt(2)/4sqrt(2)= 0.50 |
| cos L | Length of leg adjacent to∠L/Length of hypotenuse | 2sqrt(6)/4sqrt(2)=sqrt(3)/2≈ 0.87 |
| tan L | Length of leg opposite to∠L/Length of leg adjacent to∠L | 2sqrt(2)/2sqrt(6)=sqrt(3)/3≈ 0.58 |
a/b=.a /2./.b /2.
a/b=a * sqrt(2)/b * sqrt(2)
Split into factors
sqrt(a* b)=sqrt(a)*sqrt(b)
sqrt(a)* sqrt(a)= a
a/b=.a /2./.b /2.
Next we simplified 2sqrt(6)2sqrt(2).
a/b=.a /2./.b /2.
sqrt(a)/sqrt(b)=sqrt(a/b)
Calculate quotient
Finally we simplified 2sqrt(2)2sqrt(6).
a/b=.a /2./.b /2.
a/b=a * sqrt(6)/b * sqrt(6)
Split into factors
sqrt(a* b)=sqrt(a)*sqrt(b)
sqrt(a)* sqrt(a)= a
a/b=.a /2./.b /2.