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Start by identifying the hypotenuse of the right triangle. Then find the sides that are opposite and adjacent to each angle.
Ratios for ∠J: sin J=2sqrt(5)/5≈ 0.89, cos J=sqrt(5)/5≈ 0.45, tan J=4sqrt(3)/2sqrt(3)=2.00
Ratios for ∠L: sin L=sqrt(5)/5≈ 0.45, cos L=2sqrt(5)/5≈ 0.89, tan L=2sqrt(3)/4sqrt(3)=0.50
For the given right triangle, we want to write the ratios for the sine, cosine, and tangent of ∠J and ∠L.
Let's start by identifying the hypotenuse of the triangle and the sides that are opposite and adjacent to ∠J.
| Ratio | Definition | Value |
|---|---|---|
| sin J | Length of leg opposite to∠J/Length of hypotenuse | 4sqrt(3)/2sqrt(15)=2sqrt(5)/5≈ 0.89 |
| cos J | Length of leg adjacent to∠J/Length of hypotenuse | 2sqrt(3)/2sqrt(15)=sqrt(5)/5≈ 0.45 |
| tan J | Length of leg opposite to∠J/Length of leg adjacent to∠J | 4sqrt(3)/2sqrt(3)=2.00 |
We already know the length of the hypotenuse is 2sqrt(15). Let's identify the sides that are opposite and adjacent to ∠L.
The length of the side adjacent to ∠L is 4sqrt(3) and the length of the side opposite to ∠L is 2sqrt(3). With this information, we can find the desired ratios.
| Ratio | Definition | Value |
|---|---|---|
| sin L | Length of leg opposite to∠L/Length of hypotenuse | 2sqrt(3)/2sqrt(15)=sqrt(5)/5≈ 0.45 |
| cos L | Length of leg adjacent to∠L/Length of hypotenuse | 4sqrt(3)/2sqrt(15)=2sqrt(5)/5≈ 0.89 |
| tan L | Length of leg opposite to∠L/Length of leg adjacent to∠L | 2sqrt(3)/4sqrt(3)= 0.50 |
a/b=a * sqrt(15)/b * sqrt(15)
Split into factors
sqrt(a* b)=sqrt(a)*sqrt(b)
sqrt(a)* sqrt(a)= a
a/b=.a /2./.b /2.
a/b=.a /3./.b /3.
Next we simplified 2sqrt(3)2sqrt(15).
a/b=.a /2./.b /2.
sqrt(a)/sqrt(b)=sqrt(a/b)
a/b=.a /3./.b /3.
sqrt(a/b)=sqrt(a)/sqrt(b)
Calculate root
a/b=a * sqrt(5)/b * sqrt(5)
sqrt(a)* sqrt(a)= a