McGraw Hill Glencoe Geometry, 2012
MH
McGraw Hill Glencoe Geometry, 2012 View details
4. Trigonometry
Continue to next subchapter

Exercise 62 Page 576

Start with recalling that the sum of the angle measures in a triangle is 180^(∘).

Angle Measures Side Lengths
m∠ A 53^(∘) AB 12
m∠ B 90^(∘) BC 16
m∠ C 37^(∘) AC 20
Practice makes perfect

We are given a triangle and asked to solve it, which means we need to find all angle measures and all side lengths.

Let's recall that the sum of the angle measures in a triangle is 180^(∘). Using this information, we can create an equation. (4x+1)^(∘)+ (7x-1)^(∘)+ (3x-2)^(∘)=180^(∘) Next we will solve the equation to find the value of x.
(4x+1)+(7x-1)+(3x-2)=180
4x+1+7x-1+3x-2=180
14x-2=180
14x=182
x=13
The value of x is 13. Now we will find the angle measures of △ ABC using this value.
Angle Measure Substitute Simplify
m∠ A 4(13)+1 53^(∘)
m∠ B 7(13)-1 90^(∘)
m∠ C 3(13)-2 37^(∘)

Let's add the angle measures to our picture. Notice that we found that ∠ B is a right angle.

Since △ ABC is a right triangle, we can use the trigonometric ratios to find the side lengths. Let's recall the definition of the sine of an angle. If△ ABCis a right triangle with acute∠ A, then the sine of∠ Ais the ratio of the length of the leg opposite∠ Ato the length of the hypotenuse.

Using this theorem, we can find an equation for sin 53^(∘). The length of the leg opposite to this angle is 2y+2 and the hypotenuse has a length of 3y-1. sin 53^(∘)=2y+2/3y-1 Let's solve above equation using the fact that the approximate value of sin 53^(∘) is 0.8.
sin 53^(∘)=2y+2/3y-1
0.8=2y+2/3y-1
Solve for y
0.8(3y-1)=2y+2
2.4y-0.8=2y+2
0.4y-0.8=2
0.4y=2.8
y=7
The value of y is approximately 7. Using this value, we can find all the side lengths of this triangle.
Side Length Substitute Simplify
AB 7+5 12
BC 2(7)+2 16
AC 3(7)-1 20

As we know lengths of all sides and measures of all angles, the triangle ABC is solved.