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Start with recalling that the sum of the angle measures in a triangle is 180^(∘).
Angle Measures | Side Lengths | ||
---|---|---|---|
m∠ A | 53^(∘) | AB | 12 |
m∠ B | 90^(∘) | BC | 16 |
m∠ C | 37^(∘) | AC | 20 |
We are given a triangle and asked to solve it, which means we need to find all angle measures and all side lengths.
Remove parentheses
Add and subtract terms
LHS+2=RHS+2
.LHS /14.=.RHS /14.
Angle Measure | Substitute | Simplify |
---|---|---|
m∠ A | 4(13)+1 | 53^(∘) |
m∠ B | 7(13)-1 | 90^(∘) |
m∠ C | 3(13)-2 | 37^(∘) |
Let's add the angle measures to our picture. Notice that we found that ∠ B is a right angle.
Since △ ABC is a right triangle, we can use the trigonometric ratios to find the side lengths. Let's recall the definition of the sine of an angle. If△ ABCis a right triangle with acute∠ A, then the sine of∠ Ais the ratio of the length of the leg opposite∠ Ato the length of the hypotenuse.
Side Length | Substitute | Simplify |
---|---|---|
AB | 7+5 | 12 |
BC | 2(7)+2 | 16 |
AC | 3(7)-1 | 20 |
As we know lengths of all sides and measures of all angles, the triangle ABC is solved.