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McGraw Hill Glencoe Geometry, 2012

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McGraw Hill Glencoe Geometry, 2012 View details

6. Similarity Transformations

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Exercise 44 Page 517

Use the Properties of Equality to solve the given equation. Round the solution.

1.429

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side and all of the constant terms on the other side using the Properties of Equality. In this case, the variable term is already on the right-hand side of the equation. We will simplify the fraction and use the Division Property of Equality to solve it.

80/4=14d

Calculate quotient

20=14d

.LHS /14.=.RHS /14.

20/14=d

a/b=.a /2./.b /2.

10/7=d

Rearrange equation

d=10/7

Calculate quotient

d=1.428571 ...

Round to 3 decimal place(s)

d ≈ 1.429

The solution to the equation is d ≈ 1.429.

Subchapter links

Check Your Understanding p.514

Practice and Problem Solving p.514-516

H.O.T. Problems p.516

Standardized Test Practice p.517

Spiral Review p.517

Skills Review p.517