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McGraw Hill Glencoe Geometry, 2012

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McGraw Hill Glencoe Geometry, 2012 View details

6. Similarity Transformations

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Exercise 45 Page 517

Gather all of the variable terms on one side of the equation and all of the constant terms on the other side. Then use the Properties of Equality to solve the given equation.

0.17

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side of the equation and all of the constant terms on the other side using the Properties of Equality. In this case, we need to start by using the Multiplication Property of Equality to simplify the left-hand side of the equation.

2t+15/t=92

LHS * t=RHS* t

2t+15=92t

LHS-2t=RHS-2t

15=90t

.LHS /90.=.RHS /90.

15/90=t

Now we can continue solving by simplifying the fraction.

15/90=t

a/b=.a /15./.b /15.

1/6=t

Rearrange equation

t=1/6

Calculate quotient

t=0.1666 ...

Round to 2 decimal place(s)

t ≈ 0.17

The solution to the equation is t ≈ 0.17.

Subchapter links

Check Your Understanding p.514

Practice and Problem Solving p.514-516

H.O.T. Problems p.516

Standardized Test Practice p.517

Spiral Review p.517

Skills Review p.517