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McGraw Hill Glencoe Geometry, 2012 View details

6. Similarity Transformations

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Exercise 40 Page 517

Use the Properties of Equality to solve the given equation.

5

Practice makes perfect

To solve an equation, we should first gather all of the variable terms on one side and all of the constant terms on the other side using the Properties of Equality. In this case, the variable term is already gathered on the right-hand side of the equation, so we will use the Division Property of Equality to isolate it.

145=29 * t

DivEqn

.LHS /29.=.RHS /29.

5=t

RearrangeEqn

Rearrange equation

t=5

The solution to the equation is t=5.