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Evaluate the semiperimeter, then substitute the given values into Heron's Formula.
Compare the areas evaluated using both methods.
≈ 10.9 units^2
See solution.
We are given that the Heron's Formula relates the lengths of a triangle to the area of the triangle.
A=sqrt(s(s-a)(s-b)(s-c))
The semiperimeter is 10.5. Now we will substitute the side lengths and semiperimeter into Heron's formula to evaluate the area.
Substitute values
Subtract terms
Multiply
Use a calculator
Round to 1 decimal place(s)
The area of this triangle is approximately 10.9 square units.
In this part we are asked to show that the areas found for a 5- 12- 13 right triangle are the same using Heron's formula and the standard area formula. First we will evaluate the semiperimeter of this triangle.
The semiperimeter is 15. Now we will substitute side lengths and the semiperimeter into the Heron's formula and check if the result is the same as using the standard formula. Notice that in a right triangle one leg is a base and the other is a height.
Substitute values
Subtract terms
Multiply
Calculate root
Since we ended with a true statement, we can see that both methods give us the same result.