body{margin:0;} noscript{z-index: 10000; position: fixed; display: block; height: 100%; width: 100%; background: #fff;} noscript .fa{font-size: 40px; display:block; color: #daa520;} noscript div{margin-top: 6%; padding-left: 20px; padding-right: 20px; text-align: center;} ! You must have JavaScript enabled to use this site.

McGraw Hill Glencoe Geometry, 2012

MH

McGraw Hill Glencoe Geometry, 2012 View details

1. Areas of Parallelograms and Triangles

Continue to next subchapter

Exercise 47 Page 786

What is the standard form of an equation of a circle?

x^2+y^2=36

Practice makes perfect

Let's start by recalling the standard form of an equation of a circle.

(x- h)^2+(y- k)^2= r^2 In this form, ( h, k) is the center of the circle and r is its radius. We are told that the center of the circle is at the origin, so its coordinates are ( 0, 0). We also know that its diameter is 12. The radius of a circle is half the length of the diameter so the radius of this circle is 6. This information is enough to write the equation. (x- 0)^2+(y- 0)^2= 6^2 ⇕ x^2+y^2=36

Subchapter links

Check Your Understanding p.783

Practice and Problem Solving p.783-785

H.O.T. Problems p.785

Standardized Test Practice p.786

Spiral Review p.786

Skills Review p.786