McGraw Hill Glencoe Geometry, 2012
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McGraw Hill Glencoe Geometry, 2012 View details
1. Areas of Parallelograms and Triangles
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Exercise 40 Page 785

Start by finding the base of each type of polygon. As an option, you can consider a right triangle and a rectangle.

See solution.

Practice makes perfect

Let's start by remembering the formulas to find the area of a triangle and a parallelogram.

Triangle A=b* h/2
Parallelogram A=b* h
We are told that the height must be equal to 7 units and that the area is 35 square units. Substituting these values into the first formula, we will get the measure of the base of the triangle.
A=b* h/2
35 = b * 7/2
â–Ľ
Solve for b
70 = 7b
10=b
b = 10
Then, the base of the triangle is 10 units long. Next, let's substitute the same values into the second formula.
A=b* h
35 = b * 7
â–Ľ
Solve for b
5=b
b = 5
Consequently, the base of the parallelogram is 5 units long.

Triangles

We begin by considering two parallel lines m and l that are 7 units apart. Then, we pick two points on m that are 10 units apart, and we will also pick one point on l.

By connecting these three points and moving point P along line l, we can find the three wanted triangles.
These are just three examples of triangles that have the necessary base and height.

Parallelograms

To draw the required parallelograms, we start as before. We consider two lines that are 7 units apart. Then, pick two points on each line such that the distance between the points on the same line is 10 units.

Next, we connect the four points accordingly to build a parallelogram. Then, by moving points P and Q the same distance and the same direction along line l, we will get the three wanted parallelograms.
These are just three examples of parallelograms that have the necessary base and height.